Projectile Motion Velocity Math

In projectile motion problems up is defined as the positive direction so the y component has a magnitude of 49 0 m s in the down direction.

Projectile motion velocity math. Its height h in feet above the ground is modeled by the function. Equations related to the projectile motion is given as. Let the projectile meet the inclined plane at a point p x y. Then x rcos β and y rsin β so p x y rcos β rsin β.

Duration of flight there is no vertical component in the initial velocity mathrm v 0 because the object is launched horizontally. Note that d has its maximum value when. V o is the initial velocity. For instance the gravitational force on earth is a downward 32 ft s 2 but we used 16 in the equation.

So g for my equation this time will by 98 2 49. Sin θ is the component along the y axis. A projectile is launched from a tower into the air with initial velocity of 48 feet per second. The ball is thrown horizontally so the initial vertical velocity 0 m s and the initial horizontal velocity 25 m s.

H 16t 2 v 0 t 64. 1 the ball s x position is given by x x0 v0t x0 0 vo 25 there is no a in the x direction 2 the ball s y position is y yo vot 1 2 a t 2 where yo 63 vo 0 a 9 8 m s 2. From the horizontal displacement the maximum distance of projectile. V2 vx2 vy2 v2 15 0 m s 2 49 0 m s 2.

Cos θ is the component along the x axis. Let a particle is projected from point o with velocity v0by making an angle α to the horizontal with β α. D v 0 t d cos θ displaystyle d v 0 t d cos theta so. To find the magnitude of the velocity the x and y components must be added with vector addition.

Where t is the time in seconds since the projectile was launched and v 0 is the initial velocity. Sin 2 θ 1. Then op r is called the range of projectile on inclined plane. D v 0 2 g sin 2 θ displaystyle d frac v 0 2 g sin 2 theta.